3x^2+6x-6.5=0

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Solution for 3x^2+6x-6.5=0 equation:



3x^2+6x-6.5=0
a = 3; b = 6; c = -6.5;
Δ = b2-4ac
Δ = 62-4·3·(-6.5)
Δ = 114
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{114}}{2*3}=\frac{-6-\sqrt{114}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{114}}{2*3}=\frac{-6+\sqrt{114}}{6} $

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